asked 56.3k views
2 votes
Can someone please help!

find the minimum value of the function f(x)=0.2x^2-x+5.2
to the nearest hundredth.

asked
User Lrsjng
by
7.4k points

1 Answer

4 votes

Answer:

min f(x) = 3.95 (for x= 2.5)

Explanation:

vertex (x) = 1/0,4 = 2,5

vertex (y) = 0.2(2.5)^2-2.5+5.2 = 3.95

answered
User Voam
by
7.7k points

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