Question

Find the area of a trapezium whose parallel sides are 34 cm and 40cm and the distance between them is 20 cm​

Answer 1

area of trapezium: 740 cm²

Explanation:

`\sf {Area \ of \ trapezium = (1)/(2)* (base \ 1 \ + base \ 2) \ * height }`

Given here:

• base 1: 34 cm
• base 2: 40 cm
• height: 20 cm

using the formula:

`\sf {Area \ of \ trapezium = (1)/(2)* (base \ 1 \ + base \ 2) \ * height }`

solve:

`\sf {(1)/(2)* (34 \ + 40) \ * 20}`

`\sf {(1)/(2)* (74) \ * 20}`

`\sf 74 * 10`

`\sf 740`