Question

If 10.00 moles of copper are reacted with 6.00 moles of sulfur according to the following balanced equation, which reactant is the limiter and how many moles of excess reactant would remain after the reaction is completed? 2 Cu + S --> Cu2S

Cu is limiting and 1.00 mole of excess S remain


S is limiting and 1.00 moles of excess Cu remain


S is limiting and 4.00 moles of excess Cu remain


Cu is limiting and 4.00 moles of excess S remain

Answer 1

Answer: Cu is limiting and 1.00 mole of excess S remain

Step-by-step explanation:

The chemical balanced reaction is:

`2Cu+S\rightarrow Cu_2S`

According to stoichiometry :

2 moles of
`Cu` require 1 mole of
`S`

Thus 10.00 moles of
`Cu` will require=
`(1)/(2)* 10.00=5.00moles` of
`S`

Thus
`Cu` is the limiting reagent as it limits the formation of product and
`S` is the excess reagent.

Moles of S left = (6.00-5.00) moles = 1.00 mole

Thus Cu is limiting and 1.00 mole of excess S remain.