Question

Circle with the center at (2,4) which goes through the point (-1,0). What is the equation of that circle?

Answer 1

(x-2)²+(y-4)² = 25

Explanation:

Standard equation of a circle is expressed as

(x-a)²+(y-b)² = r²

Center = (a, b)

Radius = r

Get the radius

r² =(0-4)²+(-1-2)²

r² = (-4)²+(-3)²

r² = 16 + 9

r² = 25

Centre = (2, 4)

Substitute into the equation

(x-2)²+(y-4)² = 25

This gives the required equation