Question

What volume would 7.83 X 10^3 moles of Nitrogen gas occupy?

Answer 1

29.232 l

Step-by-step explanation:

6.023x10^23 mole of nitrogen =22.4 l

7.83×10^23 mole of nitrogen =

22.4/(6.023×10^23)×7.83×10^23

=29.232 l