Question

A steel bullet (66.45g) located 103.15 cm above the ground is shot in the horizontal direction. It travels 360.25 cm in the horizontal direction before it hits the ground. Calculate the momentum of the steel ball in the horizontal direction. Enter your results using the measured units, i.e., grams, centimeters and seconds. Use scientific notation for this calculation.

Answer 1

The answer is "
`4950 (g\ cm )/(s)`"

Step-by-step explanation:

Consider vertical component of motion:

`\to s_y=u_yt+ (1)/(2) at^2\\\\1.0315=0+(1)/(2) * 9.81 * t^2\\\\1.0315=(1)/(2) * 9.81 * t^2\\\\1.0315=4.905 * t^2\\\\t^2= (1.0315)/(4.905)\\\\t=0.207059711\\\\`

Considering the horizontal components:

`\to v_x=x* t\\\\`

`=03.6025 * 0.207059711\\\\=0.745 (m)/(s)\\\\\to p=mv\\\\=66.45 *0.745 * 10^2\\\\=4950\ (g\ cm )/(s)`