asked 131k views
1 vote
Find the value of x. Round to the nearest tenth (one decimal place)
19
21

Find the value of x. Round to the nearest tenth (one decimal place) 19 21-example-1

2 Answers

1 vote

Answer:

x = ~8.9

Explanation:

a^2 + b^2 = c^2

c is the long side

a and b are the other two shorter sides

this means

x^2 + 19^2 = 21^2

x^2 + 361 = 441

x^2 = 441- 361

x^2 = 441- 361

x^2 = 80

square root of 80 = ~8.9

x = ~8.9

answered
User TahitianGabriel
by
8.2k points
5 votes

Using the Pythagorean theorem:

X = sqrt(21^2 - 19^2)

X = sqrt(441 - 361)

X = sqrt(80)

X = 8.944

Rounded to the nearest tenth = 8.9

answered
User Crowstar
by
7.8k points

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