Question

Which equation has both 3 and -3 as possible values of y ?

Answer 1

`{y}^(2) - 9 = 0`

Explanation:

as both 3 and - 3 are possible values of y;

`y = 3 \: or \: y = - 3`

`y - 3 = 0 \: or \: y + 3 = 0`

therefore;

`(y - 3)(y + 3) = 0`

by expanding;

`{y}^(2) - {3}^(2) = 0`

`{y }^(2) - 9 = 0`