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Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?​

Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?​
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Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?​

asked
User Artun
by
8.0k points

1 Answer

5 votes

Answer:

AD = 13

Explanation:

Area of trapezoid ABCD


= (1)/(2) (AB + AD) * AB \\ \\ 525= (1)/(2) (37+ AD) *21\\ \\ 525 * 2= (37+ AD) *21 \\ \\ 1050 = 21 * 37 + 21AD \\ \\ 1050 = 777+ 21AD \\ \\ 21AD = 1050 - 777 \\ \\ 21AD = 273 \\ \\ AD = (273)/(21) \\ \\ AD = 13

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User Jts
by
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