1. Which function does not have the set of all real numbers as its domain? A) f(x) = 3x + 7 B) f(x) = x3 - 2x2 + x – 5 C) fx= 2x-3 D) fx= x-7x+4

Question

asked Sep 7, 2022 86.5k views

1 Answer

Astrada · Answer 1 · 2022-09-11T04:50:05+0000

Answer:

None of the given functions

Explanation:

Given

$A)\ f(x) = 3x + 7$

$B)\ f(x) = x^3 - 2x^2 +x - 5$

$C)\ f(x)=2x - 3$

$D)\ f(x)=x^2 - 7x + 4$

Required

Which do not have set of real numbers as its domain

If a function has no root and no denominator, then the domain of such function is a set of all real numbers

The given functions (a) to (d) do not have square roots and do not have denominators.

Hence, all functions have the set of real numbers as their domain