Question

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What is the equation (in slope-intercept form) of a line that passes through
the point (3,-2) and has a slope of -2?
o y = 2x + 4
o y=-2x + 4
O y + 2 = -2(x + 3)
O 2x + y + 4 = 0

Answer 1

y = -2x + 4

Explanation:

to find the equation of a straight line with the slope and a pair of coordinates given

the formula is given by

y - y1 = m( x - x1)

where m is the slope and the coordinates given are (x1,y1)

By substitution,

y -(-2) = -2(x -3)

y + 2 = -2x + 6

y = -2x + 6 - 2

y = -2x +4