Question

33/2 + 3y/5 = 7y/10 + 15

Please help me solve this equation

Answer 1

Answer: y = 15

Explanation:

Answer 2

y = 15

Explanation:

`(33)/(2)` +
`(3y)/(5)` =
`(7y)/(10)` + 15

`(165)/(10)` +
`(6y)/(10)` =
`(7y)/(10)` +
`(150)/(10)` ←Find common denominator

`(15)/(10)` +
`(6y)/(10)` =
`(7y)/(10)` ←Subtract non-variable numbers

`(15)/(10)` =
`(y)/(10)` ←Cross multiply

150 = 10y ←Divide

y = 15