Question

What is the pH of 0.12M HNO3

Answer 1

pH= 0.92

Step-by-step explanation:

HNO3-> H^+ +NO3^-

HNO3 is a strong acid, so it fully dissociates

[HNO3] = 0.12M [H^+] = 0.12M

pH= -log[H^+]

pH=-log[.12] = 0.92

pH = 0.92