Question

Please help me with this problem

Answer 1

`(x+5)^2+(y-3)^2=18`

Explanation:

The standard form of a circle is
`(x-h)^(2) +(y-k)^2=r^2` were r is the radius and (h,k) is the center. We know the center is (-5,3) and the radius is the distance between (-5,3) and (-2,6) which is 3
`√(2)`. Simply substitute h = -5, k = 3, and r = 3
`√(2)` into the equation to get:

`(x+5)^2+(y-3)^2=18`

Hope this helps :)