Question

A bag contains 42 red, 45 green, 20

yellow, and 32 purple candies. You
pick one candy at random. Find the
probability that it is green or yellow.

Answer 1

Explanation:

Total sample space , n (s) = 139

no of green candies , n (g) = 45

no. of yellow candies , n (y) = 20

Probability that is green or yellow is

P( g or y) = P(g) + P(y)

= n(g) / n(s) + n (y) / n(s)

= 45 / 139 + 20 / 139

= 65 / 139

hope it will help :)

Answer 2

65/139 fraction form

0.47 decimal form