Question

Z is the center of the circle. Suppose that QR = 26, TV = 13, SV = 2x + 1, and VZ = 8. Find x and UZ.

Answer 1

X=20
26+13+1+8=58

X=2 so 58/2 is 29 so x is 29. And to find the vz you just plug it in 29 into the equation 2x+1 2(29)+1=59