asked 182k views
4 votes
If the perimeter of a rectangle is 26x^2+16x+10 and the length is 8x^2+6x+4, what is the width?

asked
User Mkl
by
7.7k points

2 Answers

5 votes

Here is the set up:

P = 2L + 2W

P = 2(26x^2+16x+10) + 2(8x^2+6x+4)

Simplify the right side to find P.

4 votes

Answer:

5x^2 + 14x + 9

To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

answered
User Summerbulb
by
7.7k points
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