Question

A rectangular lot is 75 yards wide and 120 yards long. Give the length and width of another rectangular lot that has the same perimeter but a larger area.

Answer 1

119 yds and 76 yds

Explanation:

area of 1st rect = 9000 yd^2

perimeter = 2(75+120)= 2*195=390

perimeter of 2nd rectangle = 390

l+b = 390/2= 195

the minimum l of 2nd rectangle = 119

min b of 2nd rectangle = 76

119*76 =9044