asked 150k views
2 votes
In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.

asked
User Rashadb
by
8.4k points

2 Answers

0 votes

Answer: 45.1feet

Explanation:

answered
User Suvayu
by
7.8k points
5 votes

Answer:

45.1feet

Explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

answered
User Shesha
by
8.1k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.