Question

Four charges of equal charge+q are placed at the corners of a rectangle of sides a and b.

What is the potential at the center of the rectangle if q = 2.0 uc, a = 3.0 cm, and b = 4.0cm?​

Answer 1

V = 32.2 10³ V

Step-by-step explanation:

The electric potential is a scalar quantity given by the expression

V = h ∑
`( q_i)/(r_i)`

Let's find the distance from each corner to the center of the square, using Pythagoras' theorem

r =
`(1)/(2) √(a^2 + b^2)`

indicate that all charges have the same magnitude and the casticista from each scheme to the center is r

V = k q (
`(4)/(r)`)

let's calculate

r = ½
`√(2^2 + 4^2)`Ra 2² + 4²

r = 2,236 m

V = 9 10⁹ 2 10⁻⁶ 4 / 2,236

V = 32.2 10³ V