Question

Periodic grab some phase shifts

Answer 1

The sine function is:

`y(x)=(2)/(3)sin[3\pi (x-(2\pi)/(3))]-2`

Explanation:

We need to recall that a sine function can write as:

`y(x)=Asin[B(x+C)]+D`

Where:

• A is the amplitude of the function
• B is the period
• C is the phase shift left
• D is the vertical shift

So we just need to use the listed attributes

Therefore, the sine function is:

`y(x)=(2)/(3)sin[3\pi (x-(2\pi)/(3))]-2`

I hope it helps you!