Question

In a softball game, how far must the catcher throw to second base? Round to the

nearest tenth.
84.9 ft
42.4 ft
0 120 ft
60.8 ft

Answer 1

84.9 ft

Explanation:

a^2 + b^2 = c^2

60^2 + 60^2 = c^2

3600 + 3600 = 7200

the square root of 7200

84.8528137424 ft or 84.9 ft