Question

Assume a is a positive constant. Imagine solving for x (but do not actually do so). Will your answer involve logarithms?

a = log x

Answer 1

9514 1404 393

Answer:

(b) No, 10^a is involved

Explanation:

The relationship of interest is ...

`a=\log{(x)}\ \leftrightarrow\ 10^a=x`

Determining x involves the exponential 10^a.

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When faced with problems of this sort, I like to remind myself that a logarithm is an exponent.