Question

Find the axis of symmetry and the vertex of the graph of f(x) = 4x^2-8x+3.

Answer 1

(1, -1) and x= -1

Explanation:

The vertex is (1, -1)

The parabola params are:

a=4, b=-8, c=3

v= −b/2a

- (−8)/ 2 · 4

Simplify

v=1 v=1

Plug in v=1 to find the y value

y=−1

Therefore the parabola vertex is

(1, −1)

The axis of symmetry is the line that passes through the vertex and focus.

Therefore, your axis of symmetry is

x= -1