Question

Given the equation of a circle, (x - 6)^2 + (y + 7)^2 = 64, what would the

center and radius of the circle be?

A: (6,-7); r = 64
B: (6,-7); r = 8
C: (-6, 7); r = 8
D: (6,-7); r = 32

Answer 1

B

Explanation:

Set x-6 and y+7 equal to zero to find the center

`x - 6 = 0`

`= 6`

`y + 7 = 0`

`y = - 7`

So the center is (6,-7)

Take the square root of the right side to find the radius.

`√(64) = 8`

The answer is B