Question

A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of 29.5 m. The runner starts the race at a constant speed. If she completes the 200-m dash in 24.4 s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track

Answer 1

Answer:
`2.27\ m/s^2`

Step-by-step explanation:

Given

Length of the race track
`L=200\ m`

the radius of curvature of the track
`r=29.5\ m`

time taken to run on track is
`t=24.4\ s`

Speed of runner is

`\Rightarrow v=(L)/(t)=(200)/(24.4)\\\\\Rightarrow v=8.196\ m/s`

Centripetal acceleration is

`\Rightarrow a_c=(v^2)/(r)=(8.196^2)/(29.5)\\\\\Rightarrow a_c=2.27\ m/s^2`