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3. What is the mass of a sample of alcohol (Specific heat = 2445 J/kg °C.) If it requires 4780 J of heat to raise the temperature by 5.43°C? Given Unknown Equation. Substitution…

3. What is the mass of a sample of alcohol (Specific heat = 2445 J/kg °C.) If it requires 4780 J of heat to raise the temperature by 5.43°C? Given Unknown Equation. Substitution…
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3. What is the mass of a sample of alcohol (Specific heat = 2445 J/kg °C.) If it requires

4780 J of heat to raise the temperature by 5.43°C?
Given
Unknown Equation. Substitution
Solved

asked
User Iandisme
by
7.9k points

1 Answer

5 votes

Answer:

Q=mc∆tita.

4780J= m × 2445J/kg/°C × 5.43°C

4780J= m× 13276.35J/kg

m= 0.36Kg

answered
User ILovemyPoncho
by
9.1k points
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