Question

A rectangle is 5 times as long as it is wide. The perimeter is 50 cm. Find the dimensions of the rectangle. Round to the nearest tenth if necessary.

Answer 1

Dimensions = 21 centimeters by 4.2 centimeters.

Explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangle = 50cm

Translating the word problem into an algebraic expression, we have;

L = 5W

To find the dimensions of the rectangle;

Perimeter of rectangle = 2L + 2W

50 = 2L + 2W

50 = 2(5W) + 2W

50 = 10W + 2W

50 = 12W

W = 50/12

W = 4.2 cm.

To find the length;

L = 5W

L = 5*4.2

L = 21 cm.