Question

What is the value of p?
x=1/4y^2

Answer 1

The value of p is 1

Explanation:

we know that

The standard form of the equation of a horizontal parabola is

(y - k)² = 4p(I - h)

where

(h,k) is the vertex

p
`\\eq` 0

if p > 0, the parabola opens to the right, and if p < 0, the parabola opens to the left.

In this problem we have

I =
`(1)/(4)`y²

Convert to standard form

y² 4I

The vertex is the point (0,0)

4p = 4

P = 1 -----> p > 0, the parabola opens to the right