Question

Hello, can anyone help me with this question?

Answer 1

Answer: a.
`11.9* 10^(23)atoms` of carbon

b.
`35.7* 10^(23)atoms` of hydrogen

c.
`5.96* 10^(23)atoms` of oxygen

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=(45.6g)/(46.07g/mol)=0.989moles`

a) 1 mole of ethanol
`(C_2H_5OH)` contains =
`2* 6.023* 10^(23)=12.05* 10^(23)atoms` of carbon

Thus 0.989 moles ethanol
`(C_2H_5OH)` contains =
`(12.05* 10^(23))/(1)* 0.989=11.9* 10^(23)atoms` of carbon

b) 1 mole of ethanol
`(C_2H_5OH)` contains =
`6* 6.023* 10^(23)=36.14* 10^(23)atoms` of hydrogen

Thus 0.989 moles ethanol
`(C_2H_5OH)` contains =
`(36.14* 10^(23))/(1)* 0.989=35.7* 10^(23)atoms` of hydrogen

c) 1 mole of ethanol
`(C_2H_5OH)` contains =
`6.023* 10^(23)atoms` of oxygen

Thus 0.989 moles ethanol
`(C_2H_5OH)` contains =
`(6.023* 10^(23))/(1)* 0.989=5.96* 10^(23)atoms` of oxygen