Question

In AIJK, i = 270 cm, j = 170 cm and _K=122°. Find the area of AIJK, to the

nearest square centimeter.

Answer 1

9514 1404 393

Answer:

19,463 cm²

Explanation:

The area is given by the formula ...

A = (1/2)ij·sin(K)

Filling in the values, we find the area to be ...

A = (1/2)(270 cm)(170 cm)·sin(122°) ≈ 19,463 cm²