Question

A 7.50 liter sealed jar at 18 degrees C contains 0.125 moles of oxygen and 0,125 moles of nitrogen gas. What is the pressure in the container?

Answer 1

PV = nRT —> P = nRT/V
n = 0.250 moles of gas
R = 0.08206 L atm / mol K
T = 18 + 273 = 291 K
V = 7.50 L

P = (0.250)(0.08206)(291)/(7.50) = 7.96 atm