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Х^2x+x(x^x) when x ,=2​

Х^2x+x(x^x) when x ,=2​
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3 votes
Х^2x+x(x^x) when x ,=2​

asked
User Sowrov
by
8.0k points

1 Answer

5 votes

Answer:

X= 81

your welcome :)

Explanation:

answered
User Steve Fallows
by
7.6k points
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