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1) sinACD/12.9=sin86/16.358 = ?°

2) sin53/23.0333=sinDCB/12 = ?°

asked
User Ogun
by
7.3k points

1 Answer

6 votes

Answer:

the answer is 2 sin53/23.0333=sinDCB/12 = ?°

Explanation:

answered
User Dwestgate
by
9.3k points
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