Question

4. Solid magnesium reacts with diatomic nitrogen gas to produce solid magnesium nitride.

If 2.4 grams of magnesium react in an excess of nitrogen, how many moles of
magnesium nitride are formed?

Answer 1

`\\ \rm\longmapsto 3Mg+N_2\longrightarrow M_3gN_2`

Moles of Mg:-

`\\ \rm\longmapsto (2.4)/(24)=0.1mol`

Here

• 3mol of Mg produces 1 mol magnesium nitride
• 1mol of Mg produces 0.33mol Magnesium nitride.
• 0.1mol of Mg will produce 0.33(0.1)=0.033mol Mg_3N_2