Question

A rental car company charges $31.35 per day to rent a car and $0.15 for every mile

driven. Christian wants to rent a car, knowing that:
• He plans to drive 275 miles.
• He has at most $280 to spend.
Which inequality can be used to determine d, the maximum number of days
Christian can afford to rent for while staying within his budget?

Answer 1

Explanation:

I think you got the functions typed wrong. It makes more sense if

E = .60M + 12.95

L = 1.25M +17.30

Then the difference in charges (C) would be

C = L - E = (1.25M + 17.30) - (.60M + 12.95)

Distribute the negative

C = 1.25M + 17.30 - .60M - 12.95

Combine like terms

C = 1.25M - .60M + 17.30 - 12.95

Simplify

C = .65M + 4.35

Answer 2

31.35d + 0.15(275) </= 280

Explanation:

(Daily cost x number of days) + (mileage cost x number of miles) is less than or equal to $280.

If they ask you to solve it next:

31.35d + 0.15(275) </= 280

31.35d + 41.25 </= 280

31.35d </= 238.75

d </= 7.615629998

Round it down to 7 full days

LMK if you have questions