In ΔTUV, the measure of ∠V=90°, the measure of ∠T=72°, and TU = 36 feet. Find the length of VT to the nearest tenth of a foot.

Question

asked Mar 23, 2022 180k views

2 Answers

Saad Qureshi · Answer 1 · 2022-03-29T19:17:58+0000

Answer:

11.1 feet

Step-by-step explanation:

SOH-CAH-TOA.

you use cosine to find X which is VT. cos72=x/36

which is then simplified into 36cos72 which is 11.1246118, round to nearest 10th, 11.1