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If a car drives 6.0 km north, then 8.0 km east his displacement is

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User FonZ
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Answer:

Displacement =S

S²=6²+8²

S²=36+64

S²=100

S=10km

tan●=8/6

●=53.13⁰

10km,N 53.13⁰ E

Step-by-step explanation:

The car moving to the North and to the east .the hypotenuse formed will be the displacement. This is found by using the pythagoras theorem

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User Rogger
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