Question

Can someone help me find what the “sin0=“ is for this

Answer 1

24/25

Explanation:

here's your solution

=> perpendicular = 24

=> base = 7

=> hypotenuse = ?

=> firstly we need to find hypotenuse

=> h^2 = p^2 + b^2

=> h^2 = 24^2 + 7^2

=> h^2 = 576 + 49

=> h^2 = 625

=> h = √625

=> h = 25

now sin thita = perpendicular/hypotenuse

=> 24/25

hope it helps