Register

7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =

7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =
asked 164k views
0 votes
7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =

asked
User Petek
by
7.6k points

1 Answer

2 votes
Use Socratic or mathpapa
answered
User Anthony Griggs
by
8.0k points
← Prev Question Next Question →

Related questions

User Evrim
asked Mar 24, 2021 210k views
Determine the quantity (g) of pure CaCl2 in 7.5 g of CaCl2•9H2O
Evrim asked Mar 24, 2021
by Evrim
8.9k points
1 answer
1 vote
210k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
Link Copied!