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A bag contains 8 milk and 9 dark chocolates. A sweet is selected at random. What is the probability of choosing: P(milk)= ​ P(not milk)=

A bag contains 8 milk and 9 dark chocolates. A sweet is selected at random. What is the probability of choosing: P(milk)= ​ P(not milk)=
asked 156k views
1 vote
A bag contains 8 milk and 9 dark chocolates.

A sweet is selected at random.
What is the probability of choosing:

P(milk)=
​
P(not milk)=

asked
User Brettfazio
by
8.4k points

1 Answer

6 votes

Answer

P(milk)= 8/17

P(not milk)=9/17

Because 8+9=17

hope this was helpful!!!!

answered
User McCoy
by
8.6k points
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