asked 58.5k views
5 votes
The constraint for the potential plant site 2 can be written as:

a. x21 + x22 + x23 less or equal than 2100y2
b. x21 + x22 + x23 greater or equal than 2100y2.
c. x21 + x22 + x23 less or equal than 2800 y2.
d. x21 + x22 + x23 greater or equal than 2800y2.
e. none of the above.

asked
User Nam Vu
by
9.4k points

1 Answer

2 votes

Answer:

c. x21 + x22 + x23 less or equal than 2800 y2

Explanation:

The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.

answered
User Jocheved
by
7.8k points
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