Question

Work out the size of angle BCD

Answer 1

∠BCD = 29°

Explanation:

sin 62 = BD/15

0.8829 = BD/15

BD = 13.24

tan ∠BCD = 13.24/24 = 0.5517

∠BCD = 29°

Answer 2

sin62=BD/AB

BD=Sin62×AB

BD=Sin62×15

BD=13.24

ALSO,

Tan C = BD/BC

Tan C = 13.24/24

Tan C = 5.51 / 10

C = Tan^-1 ( 5.51 / 10 )