Question

a line with a slope of 1/10 passes through the point (20,2). what is its equation in slope-intercept form?

Answer 1

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Answer:
`y= (1)/(10)x`

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Given:
`\textsf{Slope = 1/10 and goes through (20, 2)}`

Find:
`\textsf{Slope in slope-intercept form}`

Solution: First we need to plug into the point slope formula which is
`(y - y_1) = m(x - x_1)`. Let us plug in the values first and then solve for the slope-intercept form.

Plug in the values

• 
  `(y - y_1) = m(x - x_1)`

• 
  `(y - 2) = (1)/(10)(x - 20)`

Simplify

• 
  `y - 2 = ((1)/(10) * x)+((1)/(10)*-20)`

• 
  `y - 2 = (1)/(10)x-2`

• 
  `y - 2 + 2 = (1)/(10)x-2 + 2`

• 
  `y= (1)/(10)x`

Answer: Therefore, the final answer in slope-intercept form for the line with a slope of 1/10 that passes through the point (20, 2) is
`y= (1)/(10)x`