Question

Solve

e^(i*π) + 1 = 0

Using Euler's Identity

Answer 1

e^(iθ) = cosθ + isinθ

Explanation:

The Euler's identity e^(iπ) + 1 = 0 is a special case of Euler's formula e^(iθ) = cosθ + isinθ when evaluated for θ= π.

I hope this helps

Answer 2

no idea sorry hopeful someone else can help you

Explanation: