Question

A project calls for a 50 in. long board to be cut into three pieces. The first piece must be twice the length of the second piece. The third piece is 10 in. shorter than the second piece. How long must each piece be?​

Answer 1

Explanation:

la première planche = 2x

la deuxième = x

la troisième = x-10

1ere planche + 2eme planche + 3eme planche = 50 pouces

donc :

(2x) + x + (x-10) =50

4x-10 = 50

4x-10+10 = 50 +10

4x = 60

4x diviser par 4 = 60 diviser par 4

x=15

la première planche = 30

la deuxième = 15

la troisième = 5

30+15+5=50