Answer:
f1= -2+1/3
f2= 0
Explanation:
3f^2+7f=0
a = 3; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·3·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
f1=−b−Δ√2af2=−b+Δ√2a
Δ−−√=49−−√=7
f1=−b−Δ√2a=−(7)−72∗3=−146=−2+1/3
f2=−b+Δ√2a=−(7)+72∗3=06=0