Question

PLEASE HELP!!!!!!!!!!!

Answer 1

Heat change

Q1 = 27 x 4.184 x (314-273)=4631.688 J

n H₂O = 27 g : 18 g/mol = 1.5 moles

Q2 = 1.5 x 40.7 = 61.05 J

Q3 = 27 x 2.093 x (273-263)=565.11 J

Q4 = 4631.688 + 61.05 + 565.11 = 4987.848 J