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A rectangle’s length is 2a and it’s area is 2a^2+12ab. If the width of the rectangle is written in the form Pa+Qb what are P and Q?

A rectangle’s length is 2a and it’s area is 2a^2+12ab. If the width of the rectangle is written in the form Pa+Qb what are P and Q?
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A rectangle’s length is 2a and it’s area is 2a^2+12ab. If the width of the rectangle is written in the form Pa+Qb what are P and Q?

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User Alex Punnen
by
7.9k points

1 Answer

4 votes

Answer: Answer in explanation

Explanation:

P = 1 and Q = 6

divide the (2a^2+12ab) by 2a

answered
User Vlax
by
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