Question

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 27/fts. The ball's height h (in feet) after t seconds is given by the following.

h=2+27t-16t2 Find all values of t for which the ball's height is 12 feet.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Answer 1

Answer: The height of ball is 12 ft at t=0.55 and t=1.14.

Explanation:

General projectile motion is defined as

`y=-16t^(2) +vt+yo`

v is initial velocity and y₀ is initial height.

It is given that the initial height is 2 and the initial upward velocity is 27.

`y=-16t^(2) +27t+2`

The height of ball is 12 ft. Put y=12

`12=-16t^(2) +27t+2`

`0=-16t^(2) +27t-10`

t=0.549 or t=1.139

round

t=0.55 or 1.14